Python: Retrieve public URL

A simple convenience function to get the URL for an asset in a public bucket. If you do not want to use this function, you can construct the public URL by concatenating the bucket URL with the path to the asset. This function does not verify if the bucket is public. If a public URL is created for a bucket which is not public, you will not be able to download the asset.

• The bucket needs to be set to public, either via update_bucket() or by going to Storage on supabase.com/dashboard, clicking the overflow menu on a bucket and choosing "Make public"
• RLS policy permissions required:
  • buckets table permissions: none
  • objects table permissions: none
• Refer to the Storage guide on how access control works

Parameters

• path

  (Required)

  The path and name of the file to generate the public URL for. For example `folder/image.png`.

• options

  (Optional)

  undefined

Examples

Returns the URL for an asset in a public bucket

response = supabase.storage.from_("avatars").get_public_url(
  "folder/avatar1.jpg"
)

Returns the URL for an asset in a public bucket with transformations

response = supabase.storage.from_("avatars").get_public_url(
  "folder/avatar1.jpg", \{"transform": \{"width": 100, "height": 100\}\}
)

Returns the URL which triggers the download of an asset in a public bucket

response = supabase.storage.from_("avatars").get_public_url(
  "folder/avatar1.jpg", \{"download": True\}
)